给你二叉树的根节点 root ,返回其节点值的 锯齿形层序遍历 。(即先从左往右,再从右往左进行下一层遍历,以此类推,层与层之间交替进行)。
/**
* Definition for a binary tree node.
* class TreeNode {
* val: number
* left: TreeNode | null
* right: TreeNode | null
* constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
* }
*/
function zigzagLevelOrder(root: TreeNode | null): number[][] {
//层次遍历放入队列的时候反着来
if (!root) return [];
const res=[]
const queue = [root]
let left_to_right = true
while(queue.length >0){
let length = queue.length
//当前层次所遍历出来的值
const queue_val = []
for(let i=0;i<length;i++){
const node = queue.shift()
if(left_to_right){
queue_val.push(node.val)
}else {
queue_val.unshift(node.val)
}
node.left && queue.push(node.left)
node.right && queue.push(node.right)
}
res.push(queue_val)
left_to_right = !left_to_right
}
return res
};